Molar volume5/17/2023 ![]() ![]() Molarity depends upon the temperature because it deals with the volume of the solution. So we need 83.6 mL of 37% HCl to make 500 mL of 2.0 M of HCl. The required volume of stock solution (V 2) =? Molarity of (37%) stock solution (M 2) = 11.96 g/ mol The volume of the solution to prepare (V 1) = 500 cm 3 Molarity of solution to prepare (M 1) = 2.0 M For example, we have to prepare 500 mL 2.0 M HCl. Similarly, we can use this formula to make a solution of the required molarity. The average volume used is 15 mL this is calculated after performing an acid-base titrationīy putting values in the formula we can calculate the molarity of HCl, Standardization of 30 mL of HCl with 1.0M solution of sodium hydroxide (NaOH) One of the solutions is with known volume but unknown molarity whereas, the second solution is of known molarity and unknown volume. Using this formula, we can find the unknown molarity of known solutions. This formula is commonly used for titrimetric calculations and also for the standardization of solutions. ![]()
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